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2n^2+3n-9 factored completely
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2n^2+3n-9 factored completely

User Prithvi Uppalapati
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we take the factors of 2....2 and 1
factors of -9...-3 and 3

multiply the first numbers we get -6 and second numbers are 3. when we subtract them, we get our middle term of -3.

(2n - 3) (n + 3)
User Prashant Vhasure
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