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Find a linear function f (x) with slope 5 such that f (3 )=12

User Leoz
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\bf f(3)=12\iff \begin{cases} x=3\\ y=12 \end{cases}\qquad thus \\\\\\ \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 3}}\quad ,&{{ 12}})\quad % (c,d) \end{array} \\\quad \\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 5 \\ \quad \\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad \textit{plug in the values and solve for
User Brotzka
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