Answer:
![\frac1{12}](https://img.qammunity.org/2022/formulas/mathematics/high-school/mo79jm4qh2la7d75pcl3o0mku7cpqwuft4.png)
Explanation:
Outcomes for tossing a coin =2 [tail and head]
Outcomes of rolling a 6-sided die =6
Total outcomes for rolling both = 2 x 6 = 12
Favorable outcomes for getting a head and 2 on die = 1
Probability =
![(favorable\ outcome)/(Total\ outcomes)](https://img.qammunity.org/2022/formulas/mathematics/high-school/atmkkx16b2hc6wijodt3c57rd8yvyo2368.png)
Now , the probability that you will flip a heads and roll a 2
![=\frac1{12}](https://img.qammunity.org/2022/formulas/mathematics/high-school/p5nzjz55wcoo1lra2rx98ljy5zonm8dhf5.png)
Hence, the required probability =
![\frac1{12}](https://img.qammunity.org/2022/formulas/mathematics/high-school/mo79jm4qh2la7d75pcl3o0mku7cpqwuft4.png)