Answer:
x = 14
Explanation:
alanton is 16 miles from oakley, 8 miles from crawfod and 28 miles from fayeville
Make sure to draw the distances on the figure correctly.
We have similar triangles
AC CD
------ = ---------
BC CE
8 x
------ = ---------
16 28
Using cross products
8 * 28 = 16*x
224 = 16x
Divide each side 16
224/16 = 16x/16
14
The distance is 14
We have right triangles so we can find length y
y^2 + 16^2 = 28^2
y^2 = 28^2 - 16^2
y ^2 =528
y = sqrt(528)
We can find the length of AC
AC^2 +
We have right triangles so we can find length y
y^2 + 16^2 = 28^2
y^2 = 28^2 - 16^2
y ^2 =528
y = sqrt(528)