92.2k views
5 votes
How many grams of Na2CO3 are contained in 0.400 L of 0.250M Na2CO3?

1 Answer

4 votes
We have this
C M = n / V => n = C M . V = 0,25 . 0,4 = 0,1 mole
m Na2CO3 = n . M = 0,1 . 106 = 10,6 g
User Kxepal
by
8.6k points

Related questions