Question

part 2 of 2 ASSUME BOTH snowballs are thrown with the same initial speed 39.9 m/s. the first snowball is thrown at an angle of 51 degrees above the horizontal. At what angle should you throw the second snowball to make it hit the same point as the first? how many seconds after the first snowball should you throw the second so that they arrive on target at the same time?

Answer 1

Step-by-step explanation

Step 1

Let

a) for ball 1

`\begin{gathered} \text{ Initial sp}eed=v_0=33.9\text{ }(m)/(s) \\ \text{ Angle=51 \degree} \end{gathered}`

the formula for the distance is given by:

`x=(v^2_0\sin(2\theta))/(g)`

`\begin{gathered} \text{hence, let v}_0=39.9,\text{ angle= 51 \degree , g=9.8 } \\ \text{replace to solve for x } \\ x=((39.9)^2\sin(2\cdot51))/(9.8) \\ x=158.9\text{ m} \\ \end{gathered}`

hence, the horizontal distance reached by the ball 1 is 158.9 meters

Step 2

as the ball started from the same point at the same initial speed, the only way to make the second ball hits the same point as the first is thworing the second ball at the same angle, it is 51 °