7.8k views
5 votes
A teacher has a set of 12 problems to use on a math exam. The teacher makes different versions of the exam by putting 10 questions on each exam. How many different exams can the teacher make?

User Tania
by
8.1k points

2 Answers

6 votes
The teacher has to take 10 questions at a time from 12 questions.

Total ways = 12C10 = 12!/(10!)(12-10)! = 12 x 11 / 2 = 66

The teacher can make 66 different exams
User Lycana
by
7.7k points
5 votes

Answer:

66 ways

Explanation:

Given that a teacher has a set of 12 problems to use on a math exam. The teacher makes different versions of the exam by putting 10 questions on each exam.

Available questions =12

Problems to be made out of these 12 = 10

Since order does not matter in the question paper having problems, this is a question of combination.

This can be done in 12C10 ways


=(12!)/(2!10!)=66 ways

User Quanquan Liu
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories