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Let ​f(x)=x^2+12x+32.​ What are the zeros of the function?
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Let ​f(x)=x^2+12x+32.​ What are the zeros of the function?

User Zizoujab
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1 Answer

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f(x) = x^2 + 12x + 32

The zeros are x = (-4, -8)
User Alex Meyer
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