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Find the 3rd term in geometric sequence whose first term is -8 and whose common ratio is 6

User Sanka
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4 votes

Answer:

-288

Explanation:

Geometric Sequence is the sequence in which every digit is the same multiplier of its previous digit.

The formula of Geometric Sequence is:
a_(n) = a_(1)(r)^(n-1)

Here we have given that, a₁ = -8, r = 6

So, for finding the 3rd term, n = 3


a_(n) = a_(1)(r)^(n-1)


a_(3) = -8(6)^(3-1)

⇒ a₃ = -8 × 36 = -288

Thus, third term is -288.

User Miljanm
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