Question

If a ball dropped from a tower reaches the ground after 3.5 seconds, what is the height of the tower? Given: g = –9.8 meters/second2

Answer 1

Answer: 60.3

Explanation: plato

Answer 2

The distance covered by an object starting from rest
and accelerating uniformly is . . .

Distance = (1/2 of acceleration) x (time)²

= (1/2 · 9.8 m/s²) x (3.5 s)²

= (4.9 m/s²) x (3.5 s)²

= (4.9 m/s²) x (12.25 s²)

= (4.9 x 12.25) meters

= 60.025 meters