Question

How many grams of CuSO4 would be needed to make 150 mL of 0.300 M CuSO4 solution?

Answer 1

To prepare 150 mL of 0.300 M CuSO₄ solution, you would need 7.1739 grams of CuSO₄.

Step-by-step explanation:

To calculate the mass of CuSO₄ needed to make 150 mL of 0.300 M solution, use the formula:

mass (g) = molarity (M) × volume (L) × molar mass (g/mol)

First, convert the volume from milliliters to liters:

150 mL × (1 L / 1000 mL) = 0.150 L

Then, use the molar mass of CuSO4, which is 159.62 g/mol. Now, apply the formula:

mass = 0.300 M × 0.150 L × 159.62 g/mol

mass = 7.1739 g

So, you would need 7.1739 grams of CuSO₄ to make 150 mL of a 0.300 M solution.

Answer 2

You rearrange the molarity equation and plug in your given values to solve for the moles of copper (II) sulfate. You then take the moles of copper (II) sulfate times its molar mass to get the grams.