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Kite WXYZ is graphed on a coordinate plane. What is the approximate perimeter of the kite? Round to the nearest tenth. 10.6 units 11.5 units 14.0 units 16.2 units

Kite WXYZ is graphed on a coordinate plane. What is the approximate perimeter of the-example-1

2 Answers

1 vote

Answer:

D. 16.2 units.

Explanation:

We have been given an image of a kite on coordinate plane and we are asked to find the perimeter of our given kite.

Since we know that a kite has two disjoint pairs of congruent consecutive sides, so the perimeter of our given kite will be 2 times the sum of side XY and YZ.

To find the length of sides XY and YZ we will use distance formula.


\text{Distance}=√((x_2-x_1)^2+(y_2-y_1)^2)

Upon substituting coordinates of point X and Y in above formula we will get,


\text{Distance between point X and Y}=√((3-5)^2+(4-1)^2)


\text{Distance between point X and Y}=√((-2)^2+(3)^2)


\text{Distance between point X and Y}=√(4+9)


\text{Distance between point X and Y}=√(13)

Now similarly we will find the length of segment YZ.


\text{Distance between point Y and Z}=√((5-3)^2+(1--3)^2)


\text{Distance between point Y and Z}=√((2)^2+(1+3)^2)


\text{Distance between point Y and Z}=√(4+(4)^2)


\text{Distance between point Y and Z}=√(4+16)


\text{Distance between point Y and Z}=√(20)


\text{Distance between point Y and Z}=2√(5)


\text{Perimeter of kite WXYZ}=2(XY+YZ)


\text{Perimeter of kite WXYZ}=2(√(13)+2√(5))


\text{Perimeter of kite WXYZ}=2(3.6055512754639893+4.4721359549995794)


\text{Perimeter of kite WXYZ}=2(8.0776872304635687)


\text{Perimeter of kite WXYZ}=16.1553744609271374\approx 16.2

Therefore, the perimeter of the kite WXYZ is 16.2 units and option D is the correct choice.

User Shojib Flamon
by
6.6k points
6 votes

Answer-

Perimeter of the kite is 16.2 units

Solution-

As WXYZ is a kite, so two disjoint pairs of consecutive sides are congruent, i.e WX=XY and WZ=ZY

So, perimeter of the kite WXYZ is,


=2(\overline{WX}+\overline{WZ})

And


\overline{WX}=√((1-3)^2+(1-4)^2)=√((-2)^2+(-3)^2)=√(4+9)=√(13)


\overline{WZ}=√((1-3)^2+(1+3)^2)=√((-2)^2+(4)^2)=√(4+16)=√(20)

So, perimeter will be,


P=2(√(13)+√(20))=16.15\approx 16.2\ units

User Lurning Too Koad
by
6.2k points
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