123k views
3 votes
Kite WXYZ is graphed on a coordinate plane. What is the approximate perimeter of the kite? Round to the nearest tenth. 10.6 units 11.5 units 14.0 units 16.2 units

Kite WXYZ is graphed on a coordinate plane. What is the approximate perimeter of the-example-1

2 Answers

1 vote

Answer:

D. 16.2 units.

Explanation:

We have been given an image of a kite on coordinate plane and we are asked to find the perimeter of our given kite.

Since we know that a kite has two disjoint pairs of congruent consecutive sides, so the perimeter of our given kite will be 2 times the sum of side XY and YZ.

To find the length of sides XY and YZ we will use distance formula.


\text{Distance}=√((x_2-x_1)^2+(y_2-y_1)^2)

Upon substituting coordinates of point X and Y in above formula we will get,


\text{Distance between point X and Y}=√((3-5)^2+(4-1)^2)


\text{Distance between point X and Y}=√((-2)^2+(3)^2)


\text{Distance between point X and Y}=√(4+9)


\text{Distance between point X and Y}=√(13)

Now similarly we will find the length of segment YZ.


\text{Distance between point Y and Z}=√((5-3)^2+(1--3)^2)


\text{Distance between point Y and Z}=√((2)^2+(1+3)^2)


\text{Distance between point Y and Z}=√(4+(4)^2)


\text{Distance between point Y and Z}=√(4+16)


\text{Distance between point Y and Z}=√(20)


\text{Distance between point Y and Z}=2√(5)


\text{Perimeter of kite WXYZ}=2(XY+YZ)


\text{Perimeter of kite WXYZ}=2(√(13)+2√(5))


\text{Perimeter of kite WXYZ}=2(3.6055512754639893+4.4721359549995794)


\text{Perimeter of kite WXYZ}=2(8.0776872304635687)


\text{Perimeter of kite WXYZ}=16.1553744609271374\approx 16.2

Therefore, the perimeter of the kite WXYZ is 16.2 units and option D is the correct choice.

User Shojib Flamon
by
8.1k points
6 votes

Answer-

Perimeter of the kite is 16.2 units

Solution-

As WXYZ is a kite, so two disjoint pairs of consecutive sides are congruent, i.e WX=XY and WZ=ZY

So, perimeter of the kite WXYZ is,


=2(\overline{WX}+\overline{WZ})

And


\overline{WX}=√((1-3)^2+(1-4)^2)=√((-2)^2+(-3)^2)=√(4+9)=√(13)


\overline{WZ}=√((1-3)^2+(1+3)^2)=√((-2)^2+(4)^2)=√(4+16)=√(20)

So, perimeter will be,


P=2(√(13)+√(20))=16.15\approx 16.2\ units

User Lurning Too Koad
by
7.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.