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The height above the ground of a ball thrown up with a velocity of 96 feet per second from a height of 6 feet is 6+96t-16t² feet, where t is the time in seconds. according to this model, how high is the
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The height above the ground of a ball thrown up with a velocity of 96 feet per second from a height of 6 feet is 6+96t-16t² feet, where t is the time in seconds. according to this model, how high is the ball after 7 seconds? Explain.

User Kirk Sefchik
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please be more specific and i can helpp you thx!
User Sean Cox
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