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A student sets up a reaction and calculates a possible yield of 55.9 grams of silver. If the student performs the reaction and the mass of actual silver obtained is 42.5 grams, what is the percent yield?

2 Answers

6 votes
The answer is 76.0%
User Doresoom
by
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6 votes

Answer : The percent yield of silver is, 76.02 %

Explanation : Given,

Theoretical yield of silver = 55.9 g

Actual yield of silver = 42.5 g

Formula used :


\%\text{ yield of silver}=\frac{\text{Actual yield of silver}}{\text{Theoretical yield of silver}}* 100

Now we put all the given values in this formula, we get the percent yield of silver.


\%\text{ yield of silver}=(42.5g)/(55.9g)* 100=76.02\%

Therefore, the percent yield of silver is, 76.02 %

User Rolan
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9.1k points