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What is the x-coordinate of the vertex of the parabola whose equation is y = 3x^2 + 12x + 5? x = -4 x = -3 x = -2
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What is the x-coordinate of the vertex of the parabola whose equation is y = 3x^2 + 12x + 5?

x = -4
x = -3
x = -2

User Cherilyn
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1 Answer

5 votes
x=-2 I am pretty sure x = -b/2a = -12/(2*3) = -2
User Renick
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