Question

PLEASE HELP. I have no idea what to do

Answer 1

What is it i can probably help

Explanation:

Answer 2

`since \to : x \sqrt[y]{ {n}^(z) } = x( {n}^{ (z)/(y) } ) \\ then \: lets \: solve \: both \: values \: separately \to : \\ \underline{ \boxed{solution \: to \: \boxed{a}}} \\ 120 \sqrt[3]{ {n}^(a) } = 3 √(n) (40 \sqrt[6]{n} ) \\ 120 \sqrt[3]{ {n}^(a) } = 3 √(n) * 40 \sqrt[6]{n} \\ 120 \sqrt[3]{ {n}^(a) } = 120 (√(n) * \sqrt[6]{n} ) \\ \sqrt[3]{ {n}^(a) } = (√(n) * \sqrt[6]{n} ) \\ {n}^{ (a)/(3) } = {n}^{ (1)/(2) } * {n}^{ (1)/(6) } \\ (a)/(3) = (1)/(2) + (1)/(6) \\ (a)/(3) = (4)/(6) \\ 6a = 12 \\ a = (12)/(6) = 2 \\ \underline{ \boxed{a = 2 \:}} \\ \\ \: \underline{ \boxed{solution \: to \: \boxed{b}}} \\ 27 \sqrt[4]{ {n}^(b) } = 3 √(n) (9 \sqrt[4]{n} ) \\ 27 \sqrt[4]{ {n}^(b) } = 3 √(n) * 9 \sqrt[4]{n} \\ 27 \sqrt[4]{ {n}^(b) } = 27 (√(n) * \sqrt[4]{n} ) \\ \sqrt[4]{ {n}^(b) } = (√(n) * \sqrt[4]{n} ) \\ {n}^{ (b)/(4) } = {n}^{ (1)/(2) } * {n}^{ (1)/(4) } \\ (b)/(4) = (1)/(2) + (1)/(4) \\ (b)/(4) = (3)/(4) \\ 4b = 12 \\ b = (12)/(4) = 3 \\ \underline{ \boxed{b = 3 \:}} \\ hence \to : \\ \underline{ \underline{\boxed{a = 2 \:}} \underline{ \boxed{b = 3 \:}}}`