Question

How to do calculate this the error? What are the rules?(Mark scheme Answer is B)

Answer 1

Here,

potential difference(V)= (2.00±0.02) V;

current (I)=( 5.3 ± 0.1) mA;

Resistance (X) will be given by

`\begin{gathered} X=(V)/(I); \\ X=\text{ }(2.00±0.02)/(5.3±0.1)\text{ }*1000\begin{cases}V={(2.00±0.02)} \\ I=({5.3±0.1\text{ \rparen mA= \lparen5.3}\pm0.1)*10^{-3\text{ }}}A\end{cases} \\ \\ \therefore X=(\text{ 377.358 }\pm0.001) \\ \text{ } \\ \end{gathered}`