Question

I dont want you to answer question for me, i have already answered it as shown in the picture. I want you to let me know if i have provided an answer worth full marks and if not tell me how i could improve it

Answer 1

`\begin{equation} √(3)-1,2 √(10) / 5, √(14), 3 √(2), √(19)+1,6 \end{equation}`

Explanation:

Given the irrational numbers:

`$3 √(2), √(3)-1, √(19)+1,6$, $2 √(10) / 5,√(14)$`

In order to arrange the numbers from the least to the greatest, we convert each number into its decimal equivalent.

`\begin{gathered} 3√(2)=3*1.414\approx4.242 \\ √(3)-1\approx1.732-1=0.732 \\ √(19)+1\approx4.3589+1=5.3589 \\ 6=6 \\ 2√(10)/5=2(3.1623)/5=1.2649 \\ √(14)=3.7147 \end{gathered}`

Finally, sort these numbers in ascending order..

`\begin{gathered} √(3)-1\approx1.732-1=0.732 \\ 2√(10)/5=2(3.1623)/5=1.2649 \\ √(14)=3.7147 \\ 3√(2)=3*1.414\approx4.242 \\ √(19)+1\approx4.3589+1=5.3589 \\ 6=6 \end{gathered}`

The given numbers in ascending order is:

`\begin{equation} √(3)-1,2 √(10) / 5, √(14), 3 √(2), √(19)+1,6 \end{equation}`

Note: In your solution, you can make the conversion of each irrational begin on a new line.