Question

I just started a new lesson and have this study guide, but the material is unfamiliar to me and

Answer 1

Answer:

2.79 eV

Step-by-step explanation:

Given

The wavelength, λ = 445 nm

The planck's constant, h = 6.626 x 10^-34 m² kg/s

The speed of light, c = 3 x 10^8 m/s

The energy of the photon is calculated as:

`\begin{gathered} E=(hc)/(\lambda) \\ \\ E=(6.626*10^(-34)*3*10^8)/(445*10^(-9)) \\ \\ E=(6.626*3)/(445)*10^(-34+8+9) \\ \\ E=0.0447*10^(-17) \\ \\ E=4.47*10^(-2)*10^(-17) \\ \\ E=4.47*10^(-19)J \end{gathered}`

But, 1 eV = 1.6 x 10^-19J

`\begin{gathered} E=(4.47*10^(-19))/(1.6*10^(-19)) \\ \\ E=2.79eV \end{gathered}`