Question

Consider the line y=7x-1 find the equation of the line that is perpendicular to this line and passes through the point (-5,6)

Answer 1

an equation for the line in​ point-slope form and general form is :
y = ax+b a : slope ; the Passing through (x' ; y')
y' = ax'+b
y-y' =a(x-x') and : x' =-5 y' =6
calculate a :
let : y = ax+b .....(D)
....y=7x-1....(D')
.(D) perpendicular to(D') : slope (D) × slope (D') = -1

slope (D') = 7
slop(D)×(7 = -1
slope (D) = -1/7
equation for the line : y-y' =a(x-x')
y-6 =(-1/7) (x+5)