Final answer:
The age of the sample in which only 10 percent of the radioactive isotope remains is slightly less than 27,000 years, based on its half-life of 9,000 years.
Step-by-step explanation:
To calculate the age of a sample in which only 10 percent of a radioactive isotope remains, we use the concept of half-life. The half-life is the time required for half of the atoms in a sample to decay. Given the half-life of the isotope is 9,000 years, we can follow a step-by-step approach to find out how many half-lives have passed to leave only 10 percent of the original isotope.
Starting with 100 percent of the isotope, after one half-life (9,000 years), 50 percent would remain. After the second half-life (18,000 years total), 25 percent would remain. Continuing this process, we can determine the number of half-lives needed to reach 10 percent:
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- After 3 half-lives (27,000 years), 12.5 percent remains.
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- To get to 10 percent, the time will be slightly less than 3 half-lives.
We know after three half-lives, 12.5 percent of the isotope remains, which is slightly more than the 10 percent remaining in the sample. Therefore, the age of the sample is a little less than 27,000 years. To approximate, we would solve the equation 0.5^n = 0.10 (where n represents the number of half-lives), but since the exact age in years is not asked for, our estimate is the sample is slightly less than 27,000 years old.