Question

a normal distribution with u= 40 with o=4 what is the probability of selecting a score greater than x=44?

Answer 1

We have the following information:'

`\begin{gathered} \mu=40 \\ \sigma=4 \\ x=44 \end{gathered}`

We want to calculate the following probability:

`P(X>44)`

then, using the information that we are given, we havE:

`P(X>44)=P(X-\mu>44-40)=P((X-\mu)/(\sigma)>(44-40)/(4))=P((X-\mu)/(\sigma)>1)`

since:

`Z=(X-\mu)/(\sigma)`

we have the following:

`P(X>44)=P(Z>1)=0.1587`

therefore, the probability of selecting a score greater than 44 is 15.87%