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Calculate the pH of a 1.840 M solution of HNO3

User Sagotharan
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1 Answer

3 votes
Data:
log10(1.8) ≈ 0.25
Solving:

pH = - log[H_(3) O^+]

pH = - log1.840 (mol/L)

pH = - log1.8*10^3

pH = 3 - 0.25

\boxed{\boxed{pH = 2.75}}\end{array}}\qquad\quad\checkmark

Note:. The pH <7, then we have an acidic solution.
User Richard Dunn
by
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