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24 votes
24 votes
Hoang has worked as a nurse at Springfield General Hospital for 6 years longer than her friend Bill. Two years ago, she had been at the hospital for twice as long. How long has each been at the hospital?

User Mateo Tibaquira
by
3.1k points

1 Answer

23 votes
23 votes

Ok let's take the information given and make an equations system with it.

I'm gonna use H for Hoang present working years and B for those of Bill. We know that right now Hoang has worked for 6 years longer than Bill, with this we can create the following equation:


H=B+6

We also have information from two years ago, at that time Hoang's working years doubled Bill's working years. One would feel tempted to write the equation H=2*B but you have to remember that this information is from the past and H and B stand for working years in the present. The correct way to approach this is change H and B by H-2 and B-2 so we consider that this information is from 2 years ago:


\begin{gathered} (H-2)=2\cdot(B-2) \\ H-2=2B-4 \\ H-2B=-2 \end{gathered}

So now we have constructed our equations system:


\begin{gathered} H=B+6 \\ H-2B=-2 \end{gathered}

Let's take the outcome of the first equation and use it in the second one:


\begin{gathered} H-2B=(B+6)-2B=-2 \\ B-2B+6=-2 \\ -B=-2-6=-8 \\ B=8 \end{gathered}

And going back to the first equation:


H=8+6=14

So Hoang has been working at the hospital for 14 years and Bill for 8 years.

User Aligator
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