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Derivative of 3x^2 + x^79

User Liviu Ilea
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1 Answer

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Answer:


\displaystyle (dy)/(dx) = 6x + 79x^(78)

General Formulas and Concepts:

Calculus

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:

Derivative Property [Addition/Subtraction]:
\displaystyle (d)/(dx)[f(x) + g(x)] = (d)/(dx)[f(x)] + (d)/(dx)[g(x)]

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Explanation:

Step 1: Define

Identify


\displaystyle y = 3x^2 + x^(79)

Step 2: Differentiate

  1. Derivative Property [Addition/Subtraction]:
    \displaystyle y' = (d)/(dx)[3x^2] + (d)/(dx)[x^(79)]
  2. Rewrite [Derivative Property - Multiplied Constant]:
    \displaystyle y' = 3(d)/(dx)[x^2] + (d)/(dx)[x^(79)]
  3. Basic Power Rule:
    \displaystyle y' = 6x + 79x^(78)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

User Kunal Puri
by
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