229k views
4 votes
The specific heat of Aluminum is 0.9 J/g K. How much heat is lost as a 100 gram sample of Aluminum is dropped into a beaker of water and its temperature drops from 100°C to 25°C?

1 Answer

3 votes
Energy=mass*SHC*temp change
=100*0.9*75
=6750J
User Eran Meir
by
7.8k points