Question

two years ago a man was six times as old as his daughter. In 18 years he will be twice as old as her, determine their present ages

Answer 1

Explanation:

Let m = man's age right now

d = daughter's age right now

m-2 = 6(d-2) => m = 6d -12 +2 = 6d-10

m+18 = 2(d+18) => m = 2d+36-18 = 2d+18

6d-10 = 2d+18

4d = 28

d = 7

m = 32