Question

A 10.-newton force is required to hold a stretched spring 0.20 meter from its rest position. What is the potential energy stored in the

stretched spring?

Answer 1

Step-by-step explanation:

Data:

Ep = ? (Joule)

if: F = k.x → F = 10 N

x (displacement) = 0.20 m

answer=1.0 j

Answer 2

Data:
Ep = ? (Joule)
if: F = k.x → F = 10 N
x (displacement) = 0.20 m

Formula:

`Ep = (F*x)/(2)`

Solving:

`Ep = (F*x)/(2)`

`Ep = (10*0.20)/(2)`

`Ep = (2)/(2)`

`\boxed{\boxed{Ep = 1\:Joule}}\end{array}}\qquad\quad\checkmark`