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A spinner has 10 equally sized sections, 8 of which are gray and 2 of which are blue. The spinner is spun twice. What is the probability that the first spin lands on gray and the second spin lands on blue?
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A spinner has 10 equally sized sections, 8 of which are gray and 2 of which are blue. The spinner is spun twice. What is the probability that the first spin lands on gray and the second spin lands on blue?

User Varevarao
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1 Answer

7 votes
p(the first spin lands on gray and the second spin lands on blue)=8/10×2/9=16/90=8/45
User MattRogowski
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