Question

Help. I got it wrong and have no clue how to get to the right answer!

Answer 1

`\bf 2x+√(4x^2)+\sqrt[3]{8x^3}\qquad \begin{cases} 4\to 2^2\\ 8\to 2^3 \end{cases}\qquad thus \\\\\\ 2x+√(2^2x^2)+\sqrt[3]{2^3x^3}\implies 2x+√((2x)^2)+\sqrt[3]{(2x)^3} \\\\\\ 2x+2x+2x=\boxed{6x}`