How many moles of KCl are required to prepare 1.50 L of 5.4 M KCl?

asked Jun 3, 2018 230k views

5 votes

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5 votes

8.1 mol KCI

This would be the answer.

SomeKittens answered Jun 5, 2018

8.1k points

2 votes

5.4 M = moles of solute / 1.50 L

Multiply both sides by 1.50 L to isolate moles of solute on the right.

8.1 mol = moles of solute

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