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If AB = 18, BC = 10, and CA = 13, list the angles of ABC in order from smallest to largest.

2 Answers

2 votes
Angle A is smallest
Then angle B
And angle C is largest

Should be correct... it may vary depending on where A, B, and C are located on the triangle
User Isaacparrot
by
6.7k points
3 votes

Answer: ∠A < ∠B < ∠C

Explanation:

Given: In Δ ABC

AB = 18, BC = 10, and CA = 13

We can see that

10<13<18

Thus, BC < CA < AB ........................(1)

We know that in triangles the larger angle to opposite to the largest side if larger.

Since, ∠A is opposite to BC

∠B is opposite to CA

∠C is opposite to AB

Therefore, from (1), we have

∠A < ∠B < ∠C

Thus, the angles of ΔABC in order from smallest to largest will be

∠A < ∠B < ∠C

User Jay Cummins
by
5.4k points