Question

A car traveling with an initial velocity of 11m/s accelerates at a constant rate of 2.8 m/s^2 for 4 second what is its velocity at the end of this time

Answer 1

Acceleration can be written as a linear equation:
y=2.8x+11 such that y is velocity and x is time.

Simply plug 4 seconds in for x and solve for y.
y=2.8(4)+11
y=11.2+11
y=22.2
The velocity at 4 seconds, therefore, is
22.2 m/s.