Question

You have 50 L of CO2 gas at standard temperature and pressure (STP). What would need to be done to the pressure to cut the volume of gas in half?

Answer 1

The pressure is doubled(2 atm)

Further explanation

Given

50 L of CO₂ gas at STP

Required

The pressure

Solution

Changing pressure, constant temperature⇒Boyle's Law

At a fixed temperature, the gas volume is inversely proportional to the pressure applied

`\tt \rm p_1V_1=p_2.V_2\\\\(p_1)/(p_2)=(V_2)/(V_1)`

STP⇒1 atm, T=273 K

The (new) volume of gas in half, so V₂=0.5 V₁ = 0.5 x 50 = 25 L

Because the gas volume is inversely proportional to the pressure than the pressure doubled = 2 atm

Or we can use the formula :

P₂=(P₁V₁)/V₂

P₂=(1 atm x 50 L)/25 L

P₂= 2 atm