Question

1-sin^2 theta/cot^2 theta
Simplify

Answer 1

sin²θ

Explanation:

Using the trigonometric identities

sin²x + cos²x = 1 ⇒ cos²x = 1 - sin²x

cotx =
`(cosx)/(sinx)`

Given

`(1-sin^20)/(cot^20)`

=
`(cos^20)/((cos^20)/(sin^20) )`

= cos²θ ×
`(sin^20)/(cos^20)` ( cancel the cos²θ )

= sin²θ