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A cone-shaped ten has a diameter of 12 ft and a height of 6 ft

What is the approximate volume of the tent?

Use 3.14 to approximate pi, and express your final answer to the nearest tenth.

User Muho
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\bf \textit{volume of a cone}=V=\cfrac{\pi r^2 h}{3}\qquad \begin{cases} r=radius=(diameter)/(2)\\ h=height\\ --------------\\ height=6\\ diameter=12\\ radius=(diameter)/(2)=(12)/(2)=6 \end{cases}
User Pberkes
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