475,981 views
12 votes
12 votes
How many grams of sodium fluoride are needed to prepare a 0.600m NaF solution that contains 600.0 g of water? Show your work.

User Hiadore
by
3.5k points

1 Answer

14 votes
14 votes

Molality (W) is the ratio of the amount of substance of a solute (in moles – n) to the mass in kilograms of the solvent (m1). It can be calculated by the following formula:

W = n/m1

Step 1 - Let's discover how many moles of sodium fluoride is needed first.

Let's transform 600 g of water to kilograms:

1 g = 0.001 kg

600 g = 0.6 kg

W = 0.600m

m1 = 0.6

0.600 = n/0.6

n = 0.36 moles of sodium floride

Step 2 - Let's transform 0.36 moles of NaF into grams. Let's use the following formula: mass = moles x molar mass

molar mass of NaF = 42 g/mol

mass = 0.36 x 42

mass = 15.12 g

Answer: 15.12 g of NaF

User Palehorse
by
2.9k points