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A 0.41kg football that is initially at rest acquires a velocity of 35m/s when it is kicked. If the kicker's boot remains in contact with the ball for 0.08s, what is the average force of the kick?
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A 0.41kg football that is initially at rest acquires a velocity of 35m/s when it is kicked. If the kicker's boot remains in contact with the ball for 0.08s, what is the average force of the kick?

User Tverghis
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4.6k points

1 Answer

5 votes

Answer:

F = 318.88[N]

Step-by-step explanation:

This problem can be solved by the principle of momentum conservation, which tells us that momentum is preserved before and after kicking the ball.

In this way, we can construct the following equation.


F*t=m*v

where:

F = force [N]

t = time = 0.08 [s]

m = mass = 0.41 [kg]

v = velocity [m/s]


F*0.045=0.41*35\\F=318.88[N]

User Richard Dalton
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4.8k points
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