Question

(4^p∙4^1)^3 simplifies to 4^q

Using the value of p that you solved for above, what is the value of the exponent q?
Explain how you found your answer. What law was used?

Answer 1

`\bf \left( 4^p\cdot 4^1 \right)^3\impliedby \textit{distributing the exponent} \\\\ \left(4^(p\cdot 3) \cdot 4^(1\cdot 3) \right)\implies 4^(3p)4^3\impliedby \begin{array}{llll} \textit{same base, different exponent}\\ \textit{add the exponents, keep the base} \end{array}`

what does it give you?