Question

Joanne bought 3 baseball cards for $160. If the first card was as expensive as the combined price of the second and the third cards, and the second card cost $20 more than the third card, what is the price of the first card?

Answer 1

$80

Explanation:

plato

Answer 2

let b represent the third card
let (b+20) represent the second card
let (2b+20) represent the first card


(2b+20)+(b+20)+b=160
4b+40=160
4b=160-40
4b=120
4b/4=120/4
b=30

2b+20
= 2(30)+20
= 60+20
= 80

b+20
= 30=20
= 60


Therefore, the first card was $80, the second card was $50 and the third card was $30.