Question

In the figure below, the segments overline RS and overline RT are tangent to the circle centered at Given that OS = 3.6 and RT = 4.8 , find OR

Answer 1

RS = 4.8

OT = 3.6

From the Pythagorean Theorem we know:

OR^2 = ST^2 + OT^2

OR^2 = 4.8^2 + 3.6^2

OR ^2 = 23.04 + 12.96

OR^2 = 36

OR = 6

Explanation: