The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?

asked Feb 8, 2018 211k views

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4 votes

5 6 7 or -7, -6, -5....................

Marshalllaw answered Feb 11, 2018

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let the numbers be 2n-2,2n,2n + 2 then sum of squares will be 12 n ^2 + 8 = 116 which implies n = 3.numbers are 4,6,8

Lambad answered Feb 12, 2018

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