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Look carefully at the diagrams of each wave.

Assume the waves A, B, C, and D each represent a different wave of the electromagnetic spectrum.

Which wave would MOST likely be energetic enough to damage living human cells and why?

Question 2 options:

a.Wave C because it's wavelength is biggest, and therefore carries the most energy.


b.Wave B because it has the shortest wavelength, and therefore carries the most energy.


c.Wave D because it has the tallest wavelength, and therefore carries the most energy.


d.Wave A because it has the biggest wavelength, and therefore carries the most energy

Look carefully at the diagrams of each wave. Assume the waves A, B, C, and D each-example-1
User Harsath
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2 Answers

4 votes
 wave b has the shortest wave length
User Rahi
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Answer : Wave B.

Explanation :

Given that, the waves A, B, C, and D each represent a different wave of the electromagnetic spectrum.

The energy of a wave is given by :


E=(hc)/(\lambda)

Where,

h is the Planck constant

c is the speed of the light


\lambda is the wavelength of light.

The wavelength of a wave is defined as the distance between two consecutive crests or troughs.

The energy of the wave is inversely proportional to its wavelength.

So, the wave that is energetic enough to damage living human cells is wave B because its wavelength is small as compared to other waves.

Hence, the correct option is (B) " Wave B because it has the shortest wavelength, and therefore carries the most energy ".

User AnotherMike
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