Question

Perpendicular lines homework

Answer 1

`\begin{gathered} m_(AC)=(7-1)/(5-(-2)) \\ m_(AC)=(6)/(7) \\ \\ \\ m_(BC)=(4-(-3))/(-3-3) \\ m_(BC)=(7)/(-6)=-(7)/(6) \end{gathered}`
`\begin{gathered} m_(AC)\cdot m_(BD)=(6)/(7)*(-(7)/(6)) \\ =-1 \\ \\ \text{ Thus the lines are perpendicular} \end{gathered}`