Answer: ΔPQS ≈ ΔPQR ≈ ΔPQS
Explanation:
In the given picture we have a right triangle PQR inw hich SQ is perpendicular to PR.
Then ΔPQS and ΔQRS are also right triangle.
Now, in ΔPQS and ΔPQR
∠PSQ=∠PQR [right angle]
∠P=∠P [common]
∴ΔPQS ≈ ΔPQR [BY AA similarity ] → (1)
In ΔPQR and ΔPQR
∠RSQ=∠PQR [right angle]
∠R=∠R [common]
∴ΔPQR ≈ ΔPQR [BY AA similarity ] → (2)
From (1) and (2), we have
ΔPQS ≈ ΔPQR ≈ ΔPQS
Because if two triangles is similar to one triangle then all three triangles are similar to each other [BY AA similarity ] .