Question

A sample of gas has a pressure of 1.8 atm and a volume of 2.5 L, what would be the pressure of this sample of gas if the volume decreases to 1.2 L? Show all of the work used to solve this problem.

Answer 1

Boyle's Law
P1V1 = P2V2
1.8 atm * 2.5 L = P2 * 1.2 L
1.8 atm * 2.5 L / 1.2 L = P2
3.75 atm = P2
Using significant digits, the answer is 3.8 atm

Answer 2

Answer: 3.75 atm

Step-by-step explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

`P\propto (1)/(V)` (At constant temperature and number of moles)

`P_1V_1=P_2V_2`

where,

`P_1` = initial pressure of gas = 1.8 atm

`P_2` = final pressure of gas = ?

`V_1` = initial volume of gas = 2.5 L

`V_2` = final volume of gas = 1.2 L

Now put all the given values in the above equation, we get the final pressure of gas.

`1.8* 2.5=P_2* 1.2`

`P_2=3.75atm`

Therefore, the final pressure of the gas will be 3.75 atm