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Find dy/dx when y=0 if xcosy-sinx-2=0

User Prasad D
by
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xcos(y) --> For this part, use the product rule, which would mean
cosy - xsiny * dy/dx

sinx's derivative is just cosx, so we get as a final answer

cosy - xsiny * dy/dx - cosx =0
-xsiny *dy/dx = cosx - cosy
dy/dx = cosx - cosy / -xsiny

When y=0,
dy/dx = cosx - cosy / -xsiny
dy/dx = cosx - cos(0) / -xsin(0) [note: sin(0) =0]
dy/dx = undefined [since you can't divide by 0]
User Andi Krusch
by
8.3k points

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