Question

Y=-x^2+x+12 write in intercept form and show work

Answer 1

Given that y= x^2+x+12, to write the expression in an intercept form we need to factorize the expression.

`y=-x^2+x+12`

The intercept form is of the format

`y=a(x\pm p)(x\pm q)_{}`

This is obtained by factoring the quadratic equation above

`\begin{gathered} y=-x^2+4x-3x+12 \\ y=-x(x-4)-3(x-4) \\ y=(x-4)(-x-3) \\ y=-1(x+3)(x-4) \end{gathered}`

Hence, the intercept form of the equation is y= -1 (x + 3) ( x - 4 )