Question

What is the equation, in point-slope form, that is perpendicular to the given line and passes through the point (-4,-3)?

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Answer 1

C. y + 3 = ¼(x + 4)

Explanation:

✔️First, find the slope of the given line on the graph that it is perpendicular to:

Slope (m) = ∆y/∆x = -4/1 = -4

Thus, the slope of the line that is perpendicular to the given line would be the negative reciprocal of -4.

The negative reciprocal of -4 = ¼

✔️Find the equation in point-slope form, y - b = m(x - a) using slope and a point on the line:

Substitute m = ¼, (a, b) = (-4, -3) into y - b = m(x - a):

y - (-3) = ¼(x - (-4))

y + 3 = ¼(x + 4)