Question

In TUV, the measure of V=90°, the measure of U=58°, and TU = 38 feet. Find the length of VT to the nearest tenth of a foot.

Answer 1

32.2 feet

Step-by-step explanation:

The diagram given is a right angled triangle

Using the SOH CAH TOA identity

Given the following

Hypotenuse = 38

Opposite = x

Sin theta = opposite/hypotenuse

Sin 58 = x/38

x = 38sin58

x = 38(0.8480)

x = 32.23

Hence the length of VT to the nearest tenth of a foot. is 32.2feet